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5^-8 x 5^4 x= multiply not a variable
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so am i trying to find x?
==5^4/5^8=1/5^4
no you are mltiplying them . . . i need it in a fraction. .
do i know you mimi?
idk do you?
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\[5^{-8}\times 5^4= \frac{5^4}{5^{-8}}=\frac{1}{5^4}=\frac{1}{625}=0.0016\]
5^-8 x 5^4 using the law a^m x a^n = a^m+n 5^(-8)+4 = 5^-4 using the law a^-m = 1/a^m 1 1 5^-4 = ----- = ----- 5^4 625
in that first fraction there shouldnt be a -8, just an 8.
im gonna write this all down =)
knowledge of exponential laws is very important for solving such sums...☺
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ohhh no no, its just that my cousin uses the same name, lol sorry
hahaha thats ok =)
are you korean? or do u listen to kpop?
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