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OpenStudy (anonymous):

first try to simplify the equation by taking out a common term..
whats a term that all three sets have in common?

OpenStudy (anonymous):

c(8a^2b^2-192B^2-1)

OpenStudy (anonymous):

8

OpenStudy (anonymous):

its not 8, because the second set -1ab^2c does not have an 8

OpenStudy (anonymous):

is it like
8abc(ab-2b-24b)

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OpenStudy (anonymous):

not quite, you can't take the 8 out because it's not common for all three sets

OpenStudy (anonymous):

mmm..........i dont think sooo

OpenStudy (anonymous):

its some thing like i wrote...

OpenStudy (anonymous):

look at the sets independently:
8a^2b^2c-1^ab^2c-192b^2c
\[8a^2b^2c\]\[-1^2ab^2c\]\[-192b^2c\]
what do these three sets have in common?

OpenStudy (anonymous):

c

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OpenStudy (anonymous):

yes, and what else?

OpenStudy (anonymous):

ab

OpenStudy (anonymous):

a is not common because the last term -192b^2c does not have an a
and b is common, but you're missing a part of it
when i say what is common, i mean what is the same in each set?

OpenStudy (anonymous):

b^2

OpenStudy (anonymous):

exactly! and your first answer was right too, so there's b^2c
try factoring that out of the equation

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