Mathematics
OpenStudy (anonymous):

factor 8a^2b^2c-1^ab^2c-192b^2c

OpenStudy (anonymous):

first try to simplify the equation by taking out a common term.. whats a term that all three sets have in common?

OpenStudy (anonymous):

c(8a^2b^2-192B^2-1)

OpenStudy (anonymous):

8

OpenStudy (anonymous):

its not 8, because the second set -1ab^2c does not have an 8

OpenStudy (anonymous):

is it like 8abc(ab-2b-24b)

OpenStudy (anonymous):

not quite, you can't take the 8 out because it's not common for all three sets

OpenStudy (anonymous):

mmm..........i dont think sooo

OpenStudy (anonymous):

its some thing like i wrote...

OpenStudy (anonymous):

look at the sets independently: 8a^2b^2c-1^ab^2c-192b^2c \[8a^2b^2c\]\[-1^2ab^2c\]\[-192b^2c\] what do these three sets have in common?

OpenStudy (anonymous):

c

OpenStudy (anonymous):

yes, and what else?

OpenStudy (anonymous):

ab

OpenStudy (anonymous):

a is not common because the last term -192b^2c does not have an a and b is common, but you're missing a part of it when i say what is common, i mean what is the same in each set?

OpenStudy (anonymous):

b^2

OpenStudy (anonymous):

exactly! and your first answer was right too, so there's b^2c try factoring that out of the equation

OpenStudy (anonymous):