factor 8a^2b^2c-1^ab^2c-192b^2c
first try to simplify the equation by taking out a common term.. whats a term that all three sets have in common?
c(8a^2b^2-192B^2-1)
8
its not 8, because the second set -1ab^2c does not have an 8
is it like 8abc(ab-2b-24b)
not quite, you can't take the 8 out because it's not common for all three sets
mmm..........i dont think sooo
its some thing like i wrote...
look at the sets independently: 8a^2b^2c-1^ab^2c-192b^2c \[8a^2b^2c\]\[-1^2ab^2c\]\[-192b^2c\] what do these three sets have in common?
c
yes, and what else?
ab
a is not common because the last term -192b^2c does not have an a and b is common, but you're missing a part of it when i say what is common, i mean what is the same in each set?
b^2
exactly! and your first answer was right too, so there's b^2c try factoring that out of the equation
so can u give me the answer please
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