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\[(3 \div 3k) + (-6k+4)\div(27k)\]
\[\frac{3}{3k}+\frac{-6k+4}{27k}\]?
Yes ^
\[\frac{3}{3k}+\frac{-6k+4}{27k}=\frac{27-6k+4}{27k}=\frac{31-6k}{27k}\]
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