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Let f(x) = 2x+3 and g(x) = -x^2 + 5 Find (f of g)(x)
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fg(x) f(g(x)) f( -x^2 + 5) 2( -x^2 + 5)+3
(f of g)(x) => f(g(x)) Insert x=g(x) for f(x) f(g(x)) = 2*g(x) + 3 = 2(-x^2 + 5) + 3 = -2x^2 + 10 + 3 = -2x^2 + 13
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