Question

Write the equation of the line that passes through (3,5) and (6,6) in slope-intercept form.

Answer 1

slope is 1/3; y-5=1/3(x-3)

Answer 2

The Work.?

Answer 3

then solve for y=

Answer 4

slope formula: y2-y1/x2-x1 and then point slope formula y-y1=m(x-x1)

Answer 5

Okay Wait..

Answer 6

I know the answer is y=1/3x+4 . But how do I do the work.?

Answer 7

I gave you the formulas. Plug and chug

Answer 8

Okay This is all I got.

Answer 9

y2-y1 = 6-5=1
x2-x1 = 6-(3)
y=mx+b
6=1/3 (6) + b

Answer 10

Then, I don't know what to do.

Answer 11

6=2b so b=3 is what it looks like

Answer 12

But then the answer won't be 1/3x+4 though. :\

Answer 13

Yes, I noticed.slope is 1/3; y-5=1/3(x-3) then y-5=1/3x-1 then add 5 to -1 and that's where you get 4

Answer 14

Can You Show Me The Whole Work.? :\

Answer 15

I did. substitute the variables in the point slope formula. step 1. then distribute; step 2. Then add 5 to both sides and you are done

Answer 16

Oh.I think I get it I'll try it out.Thanks.

Answer 17

But Add 5 To What Both Sides.? IDon't Know What To Do After 6=1/3 (6) +b

Answer 18

I don't know where you are getting your equation from? y=mx+b??? but something is wrong with it. Look at my work and you add 5 to both sides of the equation.

Answer 19

First, You're Supposed To Find The Slope. Then You're Supposed To Choose Either Point And Substitute It Along With The Slope Into The Slope Intercept Form. Last, Solve For B. Right.?

Answer 20

That's The Steps I Followed Like My Teacher Said.

Answer 21

The Only Thing I'm Confused About Is, Where In The World Does 4 Come From.? >.<