Question

compute the limit
lim as x approaches 0, where f(0)=1, f'(0)=0, f''(0)=2, g(0)=0, g'(0)=1, and g''(0)=28

Answer 1

i guess you use l'hopital twice

Answer 2

scratch that it is wrong

Answer 3

i know you get 0 and 1/14 but I put 1/14 and it was wrong

Answer 4

use l'hopital once, get 0

Answer 5

oh lord scratch that too!!!

Answer 6

first off we need to know what we are taking the limit of
is it
\[\lim_{x\to 0}\frac{f(x)}{g(x)}\]??

Answer 7

yup

Answer 8

if so the limit does not exist

Answer 9

ohhhhhh is it because you can get two answers?

Answer 10

because you do not get
\[\frac{0}{0}\] you get
\[\frac{1}{0}\] so there is no limit

Answer 11

no it is because the denominator goes to zero, but the numerator goes to 1

Answer 12

if you are going to get a finite limit, and the denominator goes to zero, the numerator must go to zero as well

Answer 13

but isn't that why you go to the second and third derivatives though?

Answer 14

if the denominator goes to zero but the numerator does not, you cannot go further

Answer 15

you would use the derivative if your form was
\[\frac{0}{0}\] but it is not in this case

Answer 16

ohh ok got it! THANKS FOR THE HELP!!!

Answer 17

i don't know how to explain in any other words i am afraid
you can only go further if you have 0/0 not if you have 1/0

Answer 18

oh good.
ok
yw