compute the limit lim as x approaches 0, where f(0)=1, f'(0)=0, f''(0)=2, g(0)=0, g'(0)=1, and g''(0)=28

i guess you use l'hopital twice

scratch that it is wrong

i know you get 0 and 1/14 but I put 1/14 and it was wrong

use l'hopital once, get 0

oh lord scratch that too!!!

first off we need to know what we are taking the limit of is it \[\lim_{x\to 0}\frac{f(x)}{g(x)}\]??

yup

if so the limit does not exist

ohhhhhh is it because you can get two answers?

because you do not get \[\frac{0}{0}\] you get \[\frac{1}{0}\] so there is no limit

no it is because the denominator goes to zero, but the numerator goes to 1

if you are going to get a finite limit, and the denominator goes to zero, the numerator must go to zero as well

but isn't that why you go to the second and third derivatives though?

if the denominator goes to zero but the numerator does not, you cannot go further

you would use the derivative if your form was \[\frac{0}{0}\] but it is not in this case

ohh ok got it! THANKS FOR THE HELP!!!

i don't know how to explain in any other words i am afraid you can only go further if you have 0/0 not if you have 1/0

oh good. ok yw

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