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Mathematics
OpenStudy (anonymous):

How many liters of 18.5 molar HCl stock solution will be needed to make 25.0 liters of 1.5 molar HCl solution? Show the work used to solve this problem.

OpenStudy (mertsj):

\[V(18.5)=25(1.5)\]

OpenStudy (mertsj):

V=2.03 L

OpenStudy (anonymous):

how do you do that?? like go from the first thing to v=2.03L?

OpenStudy (mertsj):

Divide both sides by 18.5

OpenStudy (anonymous):

so how did you get 25(1.5) ?

OpenStudy (mertsj):

Volume times Normality = Volume times normality. In this case the normality is the same as the molarity

OpenStudy (anonymous):

so all i write to get credit for this problem would be : V(18.5)= 25(1.5) V=2.03L

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