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OpenStudy (anonymous):
How many liters of chlorine gas, at 278 K and 1.1 atm, will react with 25.6 grams of potassium metal? Show all of the work used to solve this problem. K + Cl2 -->2 KCl
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OpenStudy (anonymous):
2 K + Cl2 -->2 KCl Moles of Cl2: (1/2)* 25.6/39 = .328 mol Volume of Cl2: .328 * .082 * 278/ 1.1 = 6.8 L
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