Assuming all volume measurements are made at the same temperature and pressure, how many liters of water vapor can be produced when 8.23 liters of oxygen gas react with excess hydrogen gas? Show all of the work used to solve this problem.

Unbalanced equation: H2 (g) + O2 (g) H2 O(g)

Question

Assuming all volume measurements are made at the same temperature and pressure, how many liters of water vapor can be produced when 8.23 liters of oxygen gas react with excess hydrogen gas? Show all of the work used to solve this problem. 

Unbalanced equation: H2 (g) + O2 (g)  H2 O(g)

rogue · Answer

2H2 (g) + O2 (g) ---> 2H2O (g) 
1 mol of O2 yields 2 mol H2O.
Likewise, 1 L of O2 yields 2 L H2O.
So, 8.23 L O2 yields 16.46 L H2O.

anonymous · Answer

thank you(: