Question

is f'(x) of f(x)=3x^2 e^-2
x^2 -2?

Answer 1

my bad, it is e^-x

Answer 2

too bad you cant edit

Answer 3

s0 (3x^2)(e^-x)(x^2) -2 ??

Answer 4

(6xe^-x)-3x^2 e^-x
use the product rule, u will get the answer

Answer 5

F(x) = (3x^2)(e^-x)
What is f'(x)?

Answer 6

I got x^2 - 2

Answer 7

d{(3x^2)(e^-x)}/dx= 3x^2 d(e^-x)/dx + (e^-x) d(3x^2)/dx = (6xe^-x)-3x^2 e^-x

Answer 8

now factor out -3x

Answer 9

and e^-x

Answer 10

yep, it will be:
(3xe^-x)(2-x)

Answer 11

So where am i goofing up? (3x^2)(-1e^-x) + (e^-x)(6x)

Answer 12

yes

Answer 13

so -3x^2 + 6x after e^-x is factored out

Answer 14

also take common 3x

Answer 15

so we are left with -x+2?

Answer 16

yep, thats what i wrote before ^^

Answer 17

ok, I was only a little backwards. thanks

Answer 18

welcome..

Answer 19

and f''(x) is 1...

Answer 20

i have to check, but i dont think so.. again u have to apply product rule in f'(x) to find out f"(x)

Answer 21

I thought second derivitive was the derivitive of the first?