This is a very simple question

Question

anonymous · Answer

Where is the question?

anonymous · Answer

$$\sqrt{sinx +\sqrt{sinx+\sqrt{sinx+....\to \infty}}}$$
what is its derivative

anonymous · Answer

Mani I know you can solve this sum in a sec so just give the answer not the steps

mani_jha · Answer

cosx, I guess

anonymous · Answer

Mani I didn't expect this from you

mani_jha · Answer

Oh wait, cosx/(2S-1)
where S is the above function

anonymous · Answer

Why did you fail in the first try

mani_jha · Answer

I did the calculation in my mind; because you asked not to do the steps. So, I made a mistake :\

anonymous · Answer

Cheers!!!!!

anonymous · Answer

$$y = \sqrt{sinx +\sqrt{sinx + ...}}$$
so
$$y ^{2}=sinx+y$$
differentiating implicitly gives
2yy' = cosx + y'.  
Solving for y' gives
y'=cosx/(2y-1), where y is the function described above.

anonymous · Answer

love these types of problems...

anonymous · Answer

I know they look huge but actually the are so little its almost too easy