Question

This is a very simple question

Answer 1

Where is the question?

Answer 2

\[\sqrt{sinx +\sqrt{sinx+\sqrt{sinx+....\to \infty}}}\]
what is its derivative

Answer 3

Mani I know you can solve this sum in a sec so just give the answer not the steps

Answer 4

cosx, I guess

Answer 5

Mani I didn't expect this from you

Answer 6

Oh wait, cosx/(2S-1)
where S is the above function

Answer 7

Why did you fail in the first try

Answer 8

I did the calculation in my mind; because you asked not to do the steps. So, I made a mistake :\

Answer 9

Cheers!!!!!

Answer 10

\[y = \sqrt{sinx +\sqrt{sinx + ...}}\]
so
\[y ^{2}=sinx+y\]
differentiating implicitly gives
2yy' = cosx + y'.
Solving for y' gives
y'=cosx/(2y-1), where y is the function described above.

Answer 11

love these types of problems...

Answer 12

I know they look huge but actually the are so little its almost too easy