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Divide Complex number 10-5i/3-i (10-5i/3-1)(3+i/3+i) = 30-5i+5/10 = 35-5i/10 Instructors answer is 7/2-(1/2)i need to divide by 5 somehow just not sure how
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your answer is good: 35-5i/10 = 35/10 - 5i/10 = 7/2 - (1/2)i
so its just reduced by common factor of 5?
yes...
thanks
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