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\[\lim_{n \rightarrow \infty} \ln (1/n) = -\infty\] Steps please.
|dw:1331633872091:dw|
I formulated my question in a confusing way last time.
ln(1/n) = ln(1) - ln(n) = 0 - ln(n) = -ln(n) so lim(as n->inf) of -ln(n) = -ln(inf) = -inf
Thank you! I used hoptal's rule and got \[1/n(-1/n ^{2}) = -1/n\] This gave me 0 and is obviously wrong. Can you tell me what I did wrong so I don't repeat the same mistake?
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L'hopital's rule is used when you have an indeterminate case... inf/inf, inf*inf, 0/0, etc... we don't have that in this case...
But ln 0 is an error but that doesn't fall in the case, right?
right, it doesn't because ln 0 is not defined, not indeterminate.
Okay, thank you very much!
yw, np
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