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ind the distance of thepoint (-1,3,9) from a line (x-13)/5 = (y+8)/-6 = (z+3)/1
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you mean the perpendicular distance?
yes
its easy its just like 2d here we have x,y,z
im a dumb student ;-(((((
oh..wel u see i hav an xam tmrw .jst checked in here.i am sure someone else in iit group will help and thanks for joining again
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i got the answer its 12.6 if m not wronf\g
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