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Find the derivative of f(x) = x^2 sin(x)
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I did \[(x^2)(\cos(x))+(\sin(x))(2x)\] and since cos(x) + sin(x) I came up with \[x^2+2x+1\] But that was wrong.
So no you can't do that That is not an identity And even if it was you do not have cos(x)+sin(x) you have acos(x)+bsin(x)
\[x^2\cos(x)+2x \sin(x)=x(xcos(x)+2 \sin(x))\]
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