Question

how many real-number solutions does the equation have?

–7x² + 6x + 3 = 0

Answer 1

use the quadratic formula to solve the quadratics

Answer 2

b^2 - 4ac = (6)^2 - 4(-7)(3) = 36 + 84 = 120

since b^2 - 4ac> 0 i.e. b^2 - 4ac is positive so the given quadratic equation will have two real roots

Answer 3

Harkirat is using the discriminant to determine the number of solutions.
It still is the 3 possible solutions that I mentioned earlier
1 solution
2 solutions
No solution

Answer 4

@precal
pls do not confuse her...........my method is the right one to determine how many real solutions does a given quadratic equation have

Answer 5

Not confusing anyone just stating the method
\[b^2-4ac\]
is officially the discriminant

Answer 6

@ Harkirat
If the discriminant is greater than 0 then you have 2 real solutions
If the discriminant is equal to zero then you have one real solution (also known as a double root)
If the discriminant is less than 0 then you have two imaginary solutions (also known as 2 complex solutions)
What does this all mean,
It means how many times the function crosses the x axis.
two solutions (function crosses 2 places or has 2 x intercepts)
one solution (function crosses 1 place or has one x intercept)
no solution (function does not cross the x axis or no x intercept)

Answer 7

thanks guys!!!

Answer 8

anytime :)