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OpenStudy (anonymous):

factor 8a^2b^2c-1^ab^2c-192b^2c

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OpenStudy (anonymous):

know the answer????????????????

OpenStudy (anonymous):

!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (mertsj):

cool

OpenStudy (anonymous):

yeah!!!!!!!!!!know the answer???????

OpenStudy (anonymous):

What do you think it is? Then I'll help you.

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OpenStudy (anonymous):

It looks like one of the terms doesn't have an "a" so you can't factor that out. But all of them have b's and c's. So: the question is, what is the number of b's and c's the terms have in common?

OpenStudy (anonymous):

first trying to simplify it by factoring out a term that all three sets have in common

OpenStudy (anonymous):

First term: 2 b's and 1 c Second term: 2 b's and 1 c Third term: 2 b's and 1 c I'll leave the rest up to you. Tell me what you think the answer is.

OpenStudy (anonymous):

is it 8ab^2c(2b-24)

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