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OpenStudy (anonymous):
evaluate the limit (lim x-->pi/2 ) sec x
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OpenStudy (anonymous):
do you mean the limit of a limit or the limit of sec x as x approaches pi/2 ?
OpenStudy (anonymous):
Does Not Exist
OpenStudy (anonymous):
limit of (sec x) , as x approaches pi/2
OpenStudy (anonymous):
as you approach from the right the end behavior is negative infinity. as you approach from the left the end behavior is positive infinity. They don't "meet"...so the limit does not exist.
OpenStudy (anonymous):
then it's what pross said... because sec x = 1/cos x. if x = pi/2, cos (pi/2)=0 which means you have 1/0... prohibited...
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OpenStudy (anonymous):
thanks you so much
OpenStudy (anonymous):
yw, np
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