Can I get some help???
If it is simple, I can help.
Write recursive form, nth term of geometric sequence 5, 15, 45, 135,...
Is that simple @radar ?
I'm thinking.
The multiplier is 3 but need to figure out make a sequence using n.
Let me check my old algebra book.
ok
Uh oh, it is the last chapter, and chapter 13 no less. Let me look at this, (it's the first time I've seen it. lol
\[a _{n}=5(3)^{(n-1)}\] Will that do it?
Let's see lets say n=3, then a(3)=5(3^2=45. I think thats it.
using the recursive formula g sub n = 2 x g sub n-1 ....?
That would give you a difference serquence than the one you originally posted, or is this a new problem?
yes, I am asking a new question
I am assuming the g stands for the geometrical multiplier what do you want that to be the general formula for a geometrical sequence is:\[a _{n}=a _{1}r ^{n-1}\]
The r is the common ratio \[a _{1}\]is the first term
ooh ok,
Like this sequence: 6 36 216 ........ \[a _{1}=6\] r=6 and n = the number within the sequence like what would be the next sequence above it would be 6 (6)^(4-1) or\[=6\times6^{3}=1296\]
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