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Mathematics 21 Online
OpenStudy (anonymous):

Can I get some help???

OpenStudy (radar):

If it is simple, I can help.

OpenStudy (anonymous):

Write recursive form, nth term of geometric sequence 5, 15, 45, 135,...

OpenStudy (anonymous):

Is that simple @radar ?

OpenStudy (radar):

I'm thinking.

OpenStudy (radar):

The multiplier is 3 but need to figure out make a sequence using n.

OpenStudy (radar):

Let me check my old algebra book.

OpenStudy (anonymous):

ok

OpenStudy (radar):

Uh oh, it is the last chapter, and chapter 13 no less. Let me look at this, (it's the first time I've seen it. lol

OpenStudy (radar):

\[a _{n}=5(3)^{(n-1)}\] Will that do it?

OpenStudy (radar):

Let's see lets say n=3, then a(3)=5(3^2=45. I think thats it.

OpenStudy (anonymous):

using the recursive formula g sub n = 2 x g sub n-1 ....?

OpenStudy (radar):

That would give you a difference serquence than the one you originally posted, or is this a new problem?

OpenStudy (anonymous):

yes, I am asking a new question

OpenStudy (radar):

I am assuming the g stands for the geometrical multiplier what do you want that to be the general formula for a geometrical sequence is:\[a _{n}=a _{1}r ^{n-1}\]

OpenStudy (radar):

The r is the common ratio \[a _{1}\]is the first term

OpenStudy (anonymous):

ooh ok,

OpenStudy (radar):

Like this sequence: 6 36 216 ........ \[a _{1}=6\] r=6 and n = the number within the sequence like what would be the next sequence above it would be 6 (6)^(4-1) or\[=6\times6^{3}=1296\]

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