Question

Can I get some help???

Answer 1

If it is simple, I can help.

Answer 2

Write recursive form, nth term of geometric sequence
5, 15, 45, 135,...

Answer 3

Is that simple @radar ?

Answer 4

I'm thinking.

Answer 5

The multiplier is 3 but need to figure out make a sequence using n.

Answer 6

Let me check my old algebra book.

Answer 7

ok

Answer 8

Uh oh, it is the last chapter, and chapter 13 no less. Let me look at this, (it's the first time I've seen it. lol

Answer 9

\[a _{n}=5(3)^{(n-1)}\] Will that do it?

Answer 10

Let's see lets say n=3, then a(3)=5(3^2=45. I think thats it.

Answer 11

using the recursive formula g sub n = 2 x g sub n-1 ....?

Answer 12

That would give you a difference serquence than the one you originally posted, or is this a new problem?

Answer 13

yes, I am asking a new question

Answer 14

I am assuming the g stands for the geometrical multiplier what do you want that to be the general formula for a geometrical sequence is:\[a _{n}=a _{1}r ^{n-1}\]

Answer 15

The r is the common ratio
\[a _{1}\]is the first term

Answer 16

ooh ok,

Answer 17

Like this sequence: 6 36 216 ........
\[a _{1}=6\]
r=6
and n = the number within the sequence like what would be the next sequence above it would be 6 (6)^(4-1) or\[=6\times6^{3}=1296\]