Question

Math Analysis: Prove the given identity
sin 0/sin 0 + cos 0 = tan 0/1 + tan 0

Answer 1

yes

Answer 2

i think u're missing parenthesis

Answer 3

i am going to guess that this says
\[\frac{\sin(x)}{\sin(x)+\cos(x)}=\frac{\tan(x)}{1+\tan(x)}\]

Answer 4

yeah! :)

Answer 5

lol sorry ill write in (x) instead of (0) from now on.. xPP

Answer 6

told u u were missing parenthesis... No not there, here:
sin 0/(sin 0 + cos 0)

Answer 7

that is my guess in any case
and my second guess is that there is precious little trig here an amost all is algebra
if you replace cosine by "a" and sine by "b" you get
\[\frac{b}{a+b}=\frac{\frac{b}{a}}{1+\frac{b}{a}}\]

Answer 8

multiply top and bottom of the left hand side by "a" and you get your identity in one step

Answer 9

multiply top and bottom of the left hand side by "a" and you get your identity in one step

Answer 10

sorry i meant the right hand side

Answer 11

is b=1? or is that a=1?

Answer 12

An easy way, just for the question posted:
sin 0/(sin 0 + cos 0) = tan 0/(1 + tan 0)
0/(0+1) = 0/(1+0)
0/1 = 0/1
0=0
qed

Answer 13

@bahrom7893
it is
\[\theta\] not
\[0\]

Answer 14

OHHH LOL I was like.. hmm that's a joke hahahaha

Answer 15

oh wait I get it tyvm <333!!!

Answer 16

a is not 1, a is cosine
b is sine

Answer 17

i am a little slow

Answer 18

point is that there is no trig here, it is just algebra

Answer 19

no your fine, I was working on the equation while you were replying xD

Answer 20

good point

Answer 21

ty :)