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OpenStudy (anonymous):
Carbon 14 has a half-life of 1370 years. We start with 100% of Carbon 14. After how many years will there be 30% of Carbon 14 left?
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OpenStudy (anonymous):
\[.3=(\frac{1}{2})^{\frac{t}{1370}}\] solve for t
OpenStudy (anonymous):
step one \[\frac{\ln(.3)}{\ln(.5)}=\frac{t}{1370}\] step two \[t=\frac{1375\times \ln(.3)}{\ln(.5)}\] step 4 use a calculator
OpenStudy (anonymous):
i'm just wondering, why do you use ln as opposed to log?
OpenStudy (anonymous):
makes no difference
OpenStudy (anonymous):
all logs are the same, change of base formula tells you that
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OpenStudy (anonymous):
all right, thank you.
OpenStudy (anonymous):
yw
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