Question

9=(sqrt3)^(4x+6)

Answer 1

start with
\[3^2=3^{\frac{1}{2}(4x+6)}\]

Answer 2

meaning
\[2=2x+6\] and solve for x

Answer 3

x=3?

Answer 4

that is not what i get

Answer 5

can you solve
\[2=2x+6\]? it should take two steps only

Answer 6

-4

Answer 7

damn i made a mistake hold on

Answer 8

i mite be wrong

Answer 9

should be
\[2=2x+3\] so
\[-1=2x\]
\[x=-\frac{1}{2}\]

Answer 10

can u explain the steps to slove in words

Answer 11

starting where?

Answer 12

like explain the stretegy used to solve this equation

Answer 13

if you have
\[9=\sqrt{3}^{4x+6}\] would look to rewrite so the base is the same

Answer 14

the set up here is
\[9=3^2\] and
\[\sqrt{3}=3^{\frac{1}{2}}\]

Answer 15

since the bases are now the same, that means the exponents must be the same, so
\[2=\frac{1}{2}(4x+6)\] and now you have a linear equation to solve, which is a whole different problem, although a rather easy one in this case

Answer 16

u can do it all in just words beause part of my assignment is to explain the process in compltet senetnces

Answer 17

first distribute and get
\[2=2x+3\] then subtract 3 from both sides to get
\[-1=2x\] then divide by 2 and get
\[x=-\frac{1}{2}\]

Answer 18

thank u!