Why does Beryllium have a larger first Ionization energy than boron?
This is an exception to the general electronegativity trend. It can be explained by looking at the electron configurations of both elements. \[Be:[He]2s^2\] \[B:[He]2s^22p^1\] When you remove an electron from beryllium, you are taking away an electron from the 2s orbital. When you remove an electron from boron, you are taking an electron from the 2p orbital. The 2p electrons have more energy than the 2s, so it is easier to remove them as they can more strongly resist the effective nuclear charge of the nucleus.
The first ionization of Beryllium is greater than that of Boron because beryllium has a stable complete electronic configuration \[1s ^{2}2s ^{2}\]so it requires more energy to remove the first electron from it......whereas boron has the electronic configuration \[1s ^{2}2s ^{2}2p ^{1}\] which needs lesser energy than that of beryllium to remove the valence electron.........
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