Question

I need to write a formula f(x) for a rational formula using the following: vertical asymptotes x=-2 and x=4; horizontal asymptotes y=5

Answer 1

x=-2 and x=4 are the vertical asymptotes so
x+2 and x-4 are in the denominator
Horizontal asymptote =5 so
in the numerator will have 5, but still the function is not complete
Let's write what we have
\[\frac{5}{(x+2)(x-4)}\]
Now if x--->\(\infty\) y---> 5
if we take x^2 from denominator , we'll need it to get cancelled , so that y tends to a finite value
so
\[y=\frac{5x^2}{(x+2)(x-4)}\]

Answer 2

Thank you!

Answer 3

@Welcome Felicias, did you understand it?