80% of all CA drivers wear seat belts. If 3 drivers are pulled over, what's the probability that all would be wearing their seat belts? Write as a percent to the nearest tenth and explain. Thx!

Question

kinggeorge · Answer

Assuming the 3 drivers are random, there is a 8/10 chance that each individual is wearing a seat belt. If you know that, do you know how to find the probability that 3 random drivers are wearing a seatbelt?

lilai3 · Answer

uh... i don't get it....?

kinggeorge · Answer

If you have a .8 (=8/10) chance of something happening once, you have a $$\left({8\over10}\right)^3=(.8)^3 = .512 =51.2\%$$Of it happening 3 times.

lilai3 · Answer

so the answer is...51.2%?

kinggeorge · Answer

Yes. Just multiply the original probability with itself 3 times since you are pulling over 3 random drivers.

lilai3 · Answer

oh..dat's how u do it.... thank u....(dang it.. i;'m always having trouble with these.. so ya..... i appreciate dat ur giving time to answer my questions! ur da best so far! ;)

lilai3 · Answer

and is the original probability 80%?

kinggeorge · Answer

You're very welcome. :)

And yes, the original probability is 80%

lilai3 · Answer

thx