How should ticket prices be set to maximize revenue? (Round your answer to the nearest cent.) The equation is p(x)=(58000-x)/(2000).

Question

saifoo.khan · Answer

Is that complete?

lgbasallote · Answer

does this something have anything to do with optimization or calculus?

anonymous · Answer

it's a calculus problem. here is the original. 

A baseball team plays in a stadium that holds 54,000 spectators. With ticket prices at $10, the average attendance had been 38,000. When ticket prices were lowered to $8, the average attendance rose to 42,000. 

I'm just asking about part b

saifoo.khan · Answer

Maximum revenue occurs where dp/dx = 0

anonymous · Answer

so i've found p(x). at other places, people said that to find Max revenue, you use 
r(x)=x*p(x)
but i dont know what to do after that :/