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find a, b , and h so that f(x)= a sin (b(x-h)) f(x)=5cosx+2sinx
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The two given functions are equal. Break up the first one using: \[\sin(A-B)=sinAcosB-cosAsinB\] then compare with the second one. Got it? Come on, try this. It's a sum worth solving
its confusing i dont understand the procedure
Ok, Do you know the formula that I have stated above?
yea..sort of
Ok. Now see the first function: \[f(x)=a \sin (bx-bh)\] Do you agree? Now take A=bx and B=bh and then use that formula. In this formula, you've got to take sine of first angle, multiply it with cosine of the other, and then add the sine of the other multiplied by the cosine of the first. So, this becomes: \[f(x)=a(\sin bx \cos bh-\cos bx \sin bh)\] Is it clear so far?
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