Question

Let c be any constant number. Which of the following will always be perpendicular to −3x + y = 2?

Answer 1

y=2-3x

Answer 2

Alternate forms is y=2-3x
3x+y-2=0

Answer 3

It's one of these:
y = 3x + c

y = x + c

y = −3x + c

y = x + c

Answer 4

I would have to say the first one

Answer 5

-3x+c

Answer 6

oh wait NO. kumar's right

Answer 7

I thought it said parallel

Answer 8

Oh, okay.. Thanks a bunch! :DD

Answer 9

\[−3x + y = 2\rightarrow m=3\]So the slope of any perpendicular line is \[m _{\perp}=-1/3\]To get a function in terms of c as requested in the question, use general form:\[x+3y=c,c \in \mathbb{R}\]

Answer 10

-3x+y=2
y=3x+2, note that slope is 3, a perpendicular line to this will have a negative reciprocal or a slope of -1/3

Answer 11

I think you need more choices ??? I don't see a slope meeting the requirements!

Answer 12

None of your multiple choices are perpendicular to the original line.

Answer 13

... Those are the only four that were given. ;-;

Answer 14

You sure the third one down, doesn't have a 1 as a numerator and a -3 as the denominator like (-1/3)x

Answer 15

Oh. They're actually:
y = 3x + c

y = 1/3x + c

y = −3x + c

y = -1/3x + c

Answer 16

Well, which one has a slope of -1/3?

Answer 17

... The last one? xD