Question

1= -2b(lg((x+yb)/(ab))

- express the term ,,b" from this equation
- ,,lg" is logarithm in base 10
- there is logarithm of a fraction

Answer 1

i don't think you can isolate b algabraically

Answer 2

Really. The best I could come up with was
\[b/(10^{1/2b})(x+by)=1/a\]
or\[10^{1/2b}(x+by)/b=a\]

Answer 3

If you've to find b. Just substitute values of a,x and y and see

Answer 4

lg((b+xy)/ax)= 1/(-2x) --- from this equation how can be getting these results ?
b=-xy+ax
b=x(a-y)
x=b/(a-y)

Answer 5

b=-xy+ax can't be possible.
because if you substitute this in that equation:
\[\log_{}((b+xy)/ax) = -1/(2x)\]
\[\log_{}((-xy+ax+xy)/ax) = -1/(2x)\]
\[\log_{}(ax/ax) = -1/(2x)\]
or,\[0=-1/(2x)\]
or\[x=\infty\]

Answer 6

Did you encounter this problem while trying to solve another question?