Question

Given y = -1 x^2 + 4 x + (-1), find the equation of the tangent line that is horizontal to the curve.

The slope-intercept form of the equation of the tangent line that is horizontal to the curve is
y =.

Answer 1

dy/dx=0

Answer 2

dy/dx=-2x+4=0
x=2
y=3
y-y1=m(x-x1)

Answer 3

horizontal to the curve means m = 0 in a parabola this is at the stationary point


so dy/dx = -2x + 4 dy/dx = 0 when x = 2

point (2, 3) then y = 3 is the horizontal tangent

Answer 4

thanks this was correct