what does r to the power of n, r^n implies? given r is a vector..

Question

amistre64 · Answer

is r = |R| still ?

anonymous · Answer

lol im trying to clear the muddle inside my brain... LOL

amistre64 · Answer

if this is related to your last post; then it said r = |R|  where R is a vector defined function

anonymous · Answer

I think it means how many element are in vector r^2 --> r^3 --->

anonymous · Answer

ou o.o

anonymous · Answer

so i just do it normally, and ignore the n=3?

amistre64 · Answer

imrans interp would suggest that the "r" is actually a typo pf R^n

amistre64 · Answer

just do WHAT normally?

anonymous · Answer

LOL er, just differentiate it wrt to x, y, z in vector?>

amistre64 · Answer

$$\nabla r^n;\ r=|\vec R|$$

anonymous · Answer

what class is it for?

anonymous · Answer

er vector analysis 1, finish the chapter in 5hours lol. er as in differentiate lrl, without the n outside?

anonymous · Answer

sounds really advanced ,

amistre64 · Answer

you really need to post the question as a whole; just so that we can make sure we are not trying to pick up the parts midway thru

anonymous · Answer

R=xi+yj+zk, r=lRl

so i differentiate (x^2 + y^2 + z^2)^1/2 ?

anonymous · Answer

find $$\nabla r ^{?}$$

anonymous · Answer

n*

anonymous · Answer

ya its the same question T_T sry for disturbing

amistre64 · Answer

for grad(r^n) yes, take the partials of |R|^n to form a new vector with

anonymous · Answer

ty