Question

1/9^3x+1 = 27, solve for x

Answer 1

no problem I solve it
please wait

Answer 2

\[(19/10)^{3x} \times (19/10)^{1}=27\]

Answer 3

Would it be
\[1/9^{3x+1} = 3^3\]
\[3x + 1 = 3\]
3x - 2
x = 2/3 ?

Answer 4

When you did -6x-1 = 3, you put 2 - 6x
Wouldn't it be 4 = 6x? There's a negative 1 so you'd have to add it to the 3.