Question

Write a program that asks a user to enter an integer, and then print out a list of all the factors of such number, which means a list of all the number that can evenly divide into such number. For Example, if user enters 9, then your program should print out a list of fallowing numbers: 1,-1, 3, -3, 9, -9. Answer

Answer 1

I should use while looping statement
There is mistake but I don’t know where

Answer 2

#include<iostream>
using namespace std;

int main(void)
{
int input=0, i=1;

cout<< "This program displays a list of all the factors of a user–given number.\nplease enter a number for a list of factors: ";
cin>>input;

cout<< "\nThe factors for"<<input<<"are:\n";
while((input%i>0) && (i<=input)){
cout<<i<<endl;
cout<<"-"<<i<<endl;
i++;
}

return 0;
}

Answer 3

(input%i>0)
Will evaluate to false if the number you're testing isn't perfectly divisible by whatever i is. At first, it'll work with 1 since anything mod 1 is 0. But when you get to two, your program will stop because that part of the while is no longer true (unless the number is even). Instead of a while loop, use a for loop. This way it only ends when it tests all numbers.

Answer 4

If you MUST use a while loop, remove the first part of it and put it in and if placed INSIDE of the while loop. That way coming across a number that isn't a perfect divisor won't exit the loop.