Question

find the relative maximum and minimum of the equation 2x^3-3x^2-36x+2?

Answer 1

take the derivative:
y'=6x^2-6x-36

Answer 2

set it equal to 0 since it's defined everywhere

Answer 3

x^2-x-6=0

Answer 4

solve for x

Answer 5

then take the second derivative.. and plug in the x values that u get to see if it's a max or a min

Answer 6

if second derivative is positive, then ur x value is a min, if negative, it's a max