Question

Last problem :) #39

Answer 1

thx :)

Answer 2

hi again

Answer 3

hi :)

Answer 4

with this estimate \[ e^{1} = 1 + 1 +1/2\]
so:
\[\sqrt{e}\approx \sqrt{2'5}\]

Answer 5

lagrange reminder is:
\[e ^{a}x ^{3}/3\] which is e/3 at x=1, so it will be less than that
answer E

Answer 6

ok?

Answer 7

wait is this number #39?