Answer 1

\[T=2\pi \sqrt{l/g}\]
What happens when you increase g by 5% in this formula(keep l same)? Any guesses?

Answer 2

Correct. So, what happens to time period T?

Answer 3

One period is the time taken to complete one oscillation. You can say that there would be more oscillations in a particular period of time. So, time period of one oscillation increases or decreases?

Answer 4

Yes. There you go! Did you understand why should it be so?

Answer 5

A decrease in time period means that now less time will be taken for one oscillation. So, oscillations will be faster indeed.
Suppose originally the time period of a simple pendulum was 1s. If g is increases by 5%, then the time period will become 0.97 s(Using that formula).
That means, now the pendulum will complete an oscillation in only 0.97 s
Now, clear?

Answer 6

Is it a stress vs strain graph? Then, it always follow the linear relation as long as it follows Hooke's Law.

Answer 7

Yes, even if the force-position graph is linear, Hooke's law is obeyed.
Hooke's law has the form F=ax,where a is a costant and x is the position.

Answer 8

Yup.