Question

equation for line tangent to the curve.
x=-cost, y=8+sint, t=pi/2
and find the d2y/dx2

Answer 1

Where's the Equation of curve?

Answer 2

andthe equation of the curve is....

Answer 3

dx/dt=sin(t)

dy/dt=cos(t)
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dy/dx=cost/sint
dy/dx=cot (t)
d2y/dx^2=-csc^(2)t
d2y/dx^2=-csc^(2)(pi/2)
d2y/dx^2=-1

Answer 4

dy/dx=cot (t)
dy/dx=cot (pi/2)
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t=pi/2

x=-cost y=8+sint
x=0 y=8
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y-y1=m(x-x1)
y-8=cot (pi/2) (x-0)
y= x cot (pi/2) +8