The equilibrium constant Kc for the following reaction is equal to 0.20 at 250°C. Calculate the equilibrium constant Kp for the reverse reaction at the same temperature.
COCl2 (g) = CO (g) + Cl2 (g)

My Answer:
To find the reverse reaction of Kc, it should be 1/0.2 = 5, so the new Kc is 5 for the reverse reaction.

Delta G is also = -1 in the reverse reaction

So Kp = 5* (0.08206 * 523K)^-1
Kp = 0.116
I wanted to check if this was correct

Question

The equilibrium constant Kc for the following reaction is equal to 0.20 at 250°C. Calculate the equilibrium constant Kp for the reverse reaction at the same temperature. 
COCl2 (g) = CO (g) + Cl2 (g)

My Answer:
To find the reverse reaction of Kc, it should be 1/0.2 = 5, so the new Kc is 5 for the reverse reaction.

Delta G is also = -1 in the reverse reaction

So Kp = 5* (0.08206 * 523K)^-1
Kp = 0.116
I wanted to check if this was correct