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If A, B, C are invertible, then does there exist an X such that \[C^{-1}(A+X)B^{-1}=I\]?
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What I did was isolate X, and found X = CB -A. I made sure this was satisfying the equation by replacing it in the original equation: \[C^{-1}(A+X)B^{-1}=I\]\[C^{-1}(A+(CB-A))B^{-1}\]\[C^{-1}(A-A+CB)B^{-1}\]\[C^{-1}(CB)B^{-1}=II=I\] Is this appropriate to say that Yes, X exists and is CB - A? I'm not sure why I'm not sure if this is the right way to do it.
It certainly seems like the right way to do it. As long as you checked that it works, you should be fine.
Oh ok thanks =]
you're welcome
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