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Mathematics 29 Online
OpenStudy (anonymous):

what are the possible number of positive real, negative real, and complex zeros of f(x)=8x^3+13x^3-11x^2+x+9

OpenStudy (eyust707):

3

OpenStudy (eyust707):

beacuse it has degree 3... that is, the highest power is 3

OpenStudy (eyust707):

in fact that type of equation has exactly 3 roots, no more no less

OpenStudy (anonymous):

I amm still confused, is positive real, negative real, or complex zeros?

OpenStudy (eyust707):

they are just asking for the number of roots

OpenStudy (eyust707):

a polynominal in standard form will always have a number of roots equal to the degree

OpenStudy (eyust707):

FYI roots are also known as zeros

OpenStudy (anonymous):

well my choices are A: positive real:3or1, Neg real:1, complex:2or 0 B:pos. Real:2 or 0, neg real: 2or 0, complex : 4,2,0 C: pos real: 2or 0. neg real: 0, complex: 2 or 4 and D.: pos real:1, ne 3 or 1, complex: 2 or 0

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