Question

use newton's method to obtain the third approximation, x2, of the positive fourth root of 12 by calculating the third approximation of the right 0 of f(x)= x^4 -12. start with x0=1

Answer 1

so you want
\[x^4-12=0\] first guess is 1 use
\[x_2=x_1-\frac{f(x_1)}{f'(x_1)}\]

Answer 2

across! where you been?

Answer 3

\[f(1)=1^4-12=-11\]
\[f'(x)=4x^3\]
\[f'(1)=4\]
\[x_2=1-\frac{-11}{4}=\frac{15}{4}=3.75\]

Answer 4

next step is
\[3.75-\frac{f(3.75)}{f'(3.75)}\] i would use a calculator