use newton's method to obtain the third approximation, x2, of the positive fourth root of 12 by calculating the third approximation of the right 0 of f(x)= x^4 -12. start with x0=1

Question

anonymous · Answer

so you want 
$$x^4-12=0$$ first guess is 1 use 
$$x_2=x_1-\frac{f(x_1)}{f'(x_1)}$$

anonymous · Answer

across! where you been?

anonymous · Answer

$$f(1)=1^4-12=-11$$
$$f'(x)=4x^3$$
$$f'(1)=4$$
$$x_2=1-\frac{-11}{4}=\frac{15}{4}=3.75$$

anonymous · Answer

next step is 
$$3.75-\frac{f(3.75)}{f'(3.75)}$$ i would use a calculator