i have a question can someone will help me with my calculus and vectors assignment
if you post the actual information we might be able to determine if we can or cannot ....
find f^(3) (x) if f(x) = 1/sqrt(3X + 4)
the third derivative of that function right?
yes
id rewrite it as:\[(3x+4)^{-1/2}\] and work it from that angle
but how i can solve it
the derivative rules are pretty much basic and self explanatory. If you do not yet know them then it might be good for you to revisit them.
\[\frac{d}{dx}x^n=nx^{n-1}\] \[\frac{d}{dx}f(g(x))=f'(g(x))*g'(x)\] \[\frac{d}{dx}fg=f'g+fg'\] those look like the 3 that you might want to apply to this
ok
thanx
find the equations of the tangents to the curves f(x) = x^2/3 and g(x)=9/x at their point of intersection.
an equation of a tangent line needs a point and a slope to be defined. since slope IS derivative we would need to determine the derivative of each function.
then we would need to determine the point at which they actually intersect to define the "point"
y = f'(xo)x -f'(xo)xo + yo y = g'(xo)x -g'(xo)xo + yo given the point of intersection as (xo,yo)
a ball is thrown upward and forward so that after time t (in seconds) its height is h(t) = 20t-5t^2. After starting to descent it strikes a wall at a point 15m high. find the rate of descent or downward velocity of the ball at the moment of impact against the wall.
new questions should be posted on the left in order to allow more people to have an opportunity to respond to them.
oh...sorry...i didn't know that
Join our real-time social learning platform and learn together with your friends!