Question

lim(x->0) (sin8x)/x

Answer 1

l'hopital's rule...

Answer 2

yes

Answer 3

I think it is 8

Answer 4

have to find the limit

Answer 5

thank you

Answer 6

\[\frac{\frac{d(\sin8x)}{dx}}{\frac{dx}{dx}}=8\cos(8x)=8\]

Answer 7

That's the lim as x approaches 0 of course. I just don't know how to write that.

Answer 8

you can also do this myininay way

Answer 9

Let's see it.

Answer 10

\[8\times \frac{\sin(8x)}{8x}\]
\[8\times 1\]

Answer 11

What else does that apply to?

Answer 12

not sure what you mean exactly, but you could use this for
\[\lim_{x\to 0}\frac{\sin(ax)}{bx}\]

Answer 13

given of course that we grand that
\[\lim_{x\to 0}\frac{\sin(ax)}{ax}=1\] adn could also use it for
\[\lim_{x\to 0}\frac{\sin(ax)}{\sin(bx)}\]

Answer 14

You guys are way too smart for me. I'm just an old Michigan farm girl.

Answer 15

why am i not convinced?

Answer 16

I can't imagine.