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OpenStudy (anonymous):
Let f(x)=(x−6)2
. Find the average rate of change of f(x) with respect to x from x=a to x=a+h if h≠0
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myininaya (myininaya):
\[\frac{f(x_1)-f(x_0)}{x_1-x_0}\]
Just use the formula for slope
OpenStudy (anonymous):
ummm how would that end up giving me the right answer? isnt there more to the problem?
OpenStudy (anonymous):
im still just really confused haha
myininaya (myininaya):
you are given x_1=a and x_0=a+h
OpenStudy (anonymous):
okay...
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OpenStudy (anonymous):
can you show me the step by step way on how to do this please? It would help me a lot :) I'm sorry im not not fully understanding it
myininaya (myininaya):
we plug in
myininaya (myininaya):
\[\frac{f(a)-f(a+h)}{a-(a+h)}\]
OpenStudy (anonymous):
so is that the final answer?
myininaya (myininaya):
no we have to replace f(a) with (a-6)^2
and f(a+h) with (a+h-6)^2
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myininaya (myininaya):
Then simplify using algebra
myininaya (myininaya):
You will probably have to multiply some stuff out
myininaya (myininaya):
\[\frac{(a-6)^2+(a+h-6)^2}{a-(a+h)}\]
Can you play with this and simplify?
myininaya (myininaya):
oops I type-o
\[\frac{(a-6)^2-(a+h-6)^2}{a-(a+h)}\]
myininaya (myininaya):
I will show you a trick that might be helpful:
\[(a+h-6)^2=(a+h-6)(a+h-6)=([a-6]+[h])([a-6]+[h]) \]
\[=(a-6)^2+2(a-6)h+h^2 =a^2-12a+36+2a-12+h^2\]
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OpenStudy (anonymous):
Thank you!
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