Question

factor 6y^6-5y^3-4

Answer 1

this might help to y^3=x
6x^2-5x-4 then factor this
and sub back in y

Answer 2

Sorry I wasn't specific but factor in Quadratic Form

Answer 3

idk how to do quadratic form

Answer 4

This is a commonly used method; you know that it must add to be -5, and multiply to be -24. So you get \[6y ^{6} + 3y ^{3} -8y^{3}-4\]
From there, you can easily factor out, so your final solution should be
\[(3y ^{3}-4)(2y ^{3} + 1)\]

Answer 5

make it a quadratic by substituting u = y^3

then you have 6u^2 - 5u - 4 = (3u-4)(2u + 1)

replace the u with y^3

(3y^3 -4)(2y^3 +1)