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OpenStudy (anonymous):
what is the current thru the 2ohm resistor in the figure? what power is dissipated by the 2ohm resistor in the figure?
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OpenStudy (anonymous):
OpenStudy (anonymous):
ignore the current direction if it's wrong
OpenStudy (anonymous):
|dw:1332192864001:dw| Now using Kirchoff's Current Law (x-15)/4 + (x-0)/2 + (x+12-0)/4 = 0 x-15 + 2x + x+12 = 0 4x = 3 x = 3/4 I1 = (15-0.75)/4 = 14.25/4 = 3.5625 Amperes I2 = 0.375 Amperes I3 = 3.1875 Amperes
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