please someone help

What's the gravitational acceleration on a planet where the period of a 2.30 m long pendulum is 2.73 s?

Question

please someone help

What's the gravitational acceleration on a planet where the period of a 2.30 m long pendulum is 2.73 s?

anonymous · Answer

a=v^2/r
v=2pir/t 
i think its this

anonymous · Answer

um i dont think that is right wouldnt u have to use the equation g=4pi^2*[ L/T^2]?

ash2326 · Answer

You're right 
Time period of a pendulum is given by
$$T=\frac{1}{2\pi}\sqrt{\frac{L}{g}}$$
substitute L= 2.3 m and T=2.73 s
then you can find g on the planet

anonymous · Answer

oh pellet read the problem wrong! LOL 
ya you would use the one above.

anonymous · Answer

typically g is always 9.8 but its a different planet. so there is a new g.

anonymous · Answer

my answer is not coming out right

anonymous · Answer

lol nevermind... thanks for the help.. i found out my problem i was squaring the L and the T.. I was only suppose square T

anonymous · Answer

ya :P no problem man :)