So, i'm confused about the notation for stating the location of vertical asymptotes of this function s(t) = 2t / sin(t)
i know the asymptotes are located at x=n*pi, but I'm not sure how to express that in this case. Every answer I put is wrong.
so far i've tried x=3, 3pi, 3n, sin(t), -sin(t), and 0
or for that matter @imranmeah91
for what value of t is denominator 0
you're speedy
0
obiviously , t=0 but that's not all
oh, ok
sine is periodic function sin(0)=0 sin(pi)=0 sin(2pi)=0 you get the drift let n b any integer , n=0,1,2,3,4,5, sin(n pi)=0 so our verticle retricemtote is x= n pi
retricemtote=asymtote stupid autocorrect messed it up
so, does n=anything in particular, or if it true for all n?
**is it true
n has to be integer though
imranmeah91, you are fantastic. It's so neat to be able to come online with all my questions after class and find someone who will make things more clear! I really appreciate it!
you are welcome, great to hear
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