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Mathematics 9 Online
OpenStudy (anonymous):

So, i'm confused about the notation for stating the location of vertical asymptotes of this function s(t) = 2t / sin(t)

OpenStudy (anonymous):

i know the asymptotes are located at x=n*pi, but I'm not sure how to express that in this case. Every answer I put is wrong.

OpenStudy (anonymous):

so far i've tried x=3, 3pi, 3n, sin(t), -sin(t), and 0

OpenStudy (anonymous):

or for that matter @imranmeah91

OpenStudy (anonymous):

for what value of t is denominator 0

OpenStudy (anonymous):

you're speedy

OpenStudy (anonymous):

0

OpenStudy (anonymous):

obiviously , t=0 but that's not all

OpenStudy (anonymous):

oh, ok

OpenStudy (anonymous):

sine is periodic function sin(0)=0 sin(pi)=0 sin(2pi)=0 you get the drift let n b any integer , n=0,1,2,3,4,5, sin(n pi)=0 so our verticle retricemtote is x= n pi

OpenStudy (anonymous):

retricemtote=asymtote stupid autocorrect messed it up

OpenStudy (anonymous):

so, does n=anything in particular, or if it true for all n?

OpenStudy (anonymous):

**is it true

OpenStudy (anonymous):

n has to be integer though

OpenStudy (anonymous):

imranmeah91, you are fantastic. It's so neat to be able to come online with all my questions after class and find someone who will make things more clear! I really appreciate it!

OpenStudy (anonymous):

you are welcome, great to hear

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