Question

determine the specific heat of a mayterial if a 35g sample of the material absorbs 48J as it is heated from 298K to 313K

Answer 1

Q=m x c x change in T
Where T is the temperature and m is the mass and Q is the energy required and c is the specific heat capacity.
Therefore you can rearrange that to c=Q/(m x change in T)
we therefore have
c= 48/(35 x 15)
therefore we have 48/525
The answer is therefore 0.0914285714 j/k