Question

please someone help me

A bungee jumper undergoes simple harmonic motion with amplitude 5.1m and frequency 0.135 Hz. Assume the bungee jumper follows the simple harmonic motion equation x=Acos(wt).

Determine the bungee jumper's velocity at 0.25 s.
Determine the bungee jumper's velocity at 0.50 s.
Determine the bungee jumper's velocity at 1.0 s.

Answer 1

For this question
you know the displacement equation as
x=Acos(wt)
now if you differentiate a displacement function,with respect to time you get velocity
v=dx/dt
hence differentiate it you get,
v=-Awsin(wt)
over here ,you can find velocity be putting the time value
ALSO,
w=2*pi*n (n=frequency) here place value of frequency to get value of w and put it in the main equation of velocity to get your required solution!!!