Question

7u^2-4u-3 cant be factored can it?

Answer 1

What would you do to show whether it could be factored?

Answer 2

find factors of -3 that adds up to give you -4

Answer 3

well, we can't do that since we have that 7 as the leading coefficient.
We can only check -3 alone if the leading coefficient is 1

You would instead check for factors of the leading coefficient times the constant that add to -4.
7*(-3)

Answer 4

apply quadratic formula...............

Answer 5

Yah what kunal said...

Answer 6

we do not use quadratic formula for factoring

we're looking for factors of -21 that add up to -7.

Answer 7

er, add up to -4*

Answer 8

okay...

Answer 9

Won't you get
(7u-3)(u-1)

Answer 10

we'd use those factors and rewrite it in the form
7u^2 - Au + Bu - 3
then factor out of the first two terms and the last two terms

Answer 11

Did I do something wrong???

Answer 12

i got (7u-3) (u-1)

Answer 13

not quite correct... you may not be accounting for a negative somewhere

if you multiply it back together, you get
7u^2 - 7u - 3u + 3
which is 7u^2 - 10u + 3

Answer 14

O I know what I did wrong....

Answer 15

okay I see what your saying!

Answer 16

7u^ - 7u + 4u -3

Answer 17

So will it be
(7u+3)(u-1)?

Answer 18

yes, that would be correct. :)

Answer 19

yes the answer is 1 and -3/7